We consider the amplitude $T(\nu =2\mathrm{}q·p,\kappa =q^2,\delta =2\mathrm{}q·\Delta ;t={\Delta }^2)$ for the reaction $A\left(q\right)+C\left(p\right)\mathrm{}\to B\left(q^{\prime }\right)+D\left(p^1\right)$, where $A$ and $B$ are scalar currents and $C$ and $D$ are on-shell scalar particles. We assume scaling behavior, $T\underset{A}{\to }{\nu }^{-1\mathrm{}}F(\omega ,\tau ;t) \mathrm{for} \nu \to \infty$, with $\omega \equiv \frac{\kappa }{\nu }$, $\tau =\frac{\delta }{\nu }$, and $t$ fixed, and Regge behavior, $T\underset{R}{\to }{\nu }^{\alpha \mathrm{}\left(t\right)\mathrm{}}\beta (\kappa ,\delta ;t)$ for $\nu \to \infty$, with $\kappa , \delta , \mathrm{and} t$ fixed and implement these behaviors on integral representations with suitable spectral functions. For $\delta =0\mathrm{}$, we derive the commutativity relation ${\lim }_{\omega \to 0}{\lim }_{A}T={\lim }_{\kappa \to \infty }{\lim }_{R}T$ and the asymptotic behavior $f(\lambda ,0;t)\sim {\lambda }^{\alpha \mathrm{}\left(t\right)\mathrm{}}$ for the coefficient $f(x·p,x·\Delta ;t)$ of the leading light-cone (LC) singularity of the Fourier transform of $T$. [$f \mathrm{is}\mathrm{related}\mathrm{to} F \mathrm{by} F(\omega ,\tau ;t)\propto \int 0^{\infty }d\lambda e^{i\lambda \omega }f(\lambda ,\lambda \tau ;t)$.] Thus, the leading LC singularity determines the trajectory function $\alpha \mathrm{}\left(t\right)\mathrm{}$ and thus provides a configuration-space view of high-energy behavior. This generalizes our previous results for $\Delta =0\mathrm{}$. To see what can happen for $\delta \ne 0$, we use the ladder approximation for $T$. We again derive a commutativity relation ${\lim }_{\tau \to 0}{\lim }_{\omega \to 0}{\lim }_{A}T={\lim }_{\kappa \to \infty }{\lim }_{\delta \to \infty }{\lim }_{R}T, \mathrm{but}\mathrm{now} f(\lambda ,\lambda \tau ;t)\sim \mathrm{const}\ne 0$. Thus the large-$\lambda$ behavior of $f$ is quite different for $\tau =0\mathrm{}$ and for $\tau \ne 0$. This behavior can, in particular, be nice at $\tau =0\mathrm{}$, and the assumption that $0<\left|\int 0^{\infty }d\lambda f\right(\lambda ,0;t\left)\right|<\mathrm{}\infty$ is seen to lead to interesting constraints on the Regge trajectory.

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