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  • Open Access

Transverse impedance of a periodic array of cavities

A. V. Fedotov, R. L. Gluckstern, and M. Venturini

  • Physics Department, University of Maryland, College Park, Maryland 20742

Phys. Rev. ST Accel. Beams 2, 064401 – Published 21 June, 1999

DOI: https://doi.org/10.1103/PhysRevSTAB.2.064401

Abstract

We examine the transverse impedance of a periodic array of cavities in a beam pipe at high frequency. The calculation is an extension of a previous one for the longitudinal impedance of a periodic array of azimuthally symmetric pillboxes, for which only TM modes were needed. In the present case, we must include TE modes as well. In addition, we extend the applicability of the previous calculation by including an extra term in the coupling kernel so that the results are valid for all values of the ratio of the cavity length to the period of the structure (all values of the ratio of iris thickness to structure period). In spite of the presence of TE modes, we find that the high frequency limit of the transverse impedance is simply (2/ka2) times the corresponding limit of the longitudinal impedance, just as it is for the resistive wall impedances, a relation which occurs frequently for azimuthally symmetric structures. Finally, we present numerical results as well as approximate expressions for the impedance per period, valid for all ratios of cavity length to structure period.

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References (20)

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  4. We shall avoid an ambiguity which later occurs by allowing λ and μ to depart slightly from Eq. 3.4 to take into account the effect of a high but finite conductivity in the wall at r=b.
  5. At this point we note that, had we used eθ(z) rather than deθ(z)/dz in Eq. 4.9, the corresponding kernel would have been (zz)3/2, thus making that integral divergent. This has been avoided by using deθ(z)/dz.
  6. We note at this point that the behavior of ez(z) near z=0 is expected to be (kz)1/3 for kz1 (z small compared with the wavelength 2π/k). Thus (kz)1/2 in the denominator of Eq. 4.11 should be replaced by (kz)1/2+const(kz)1/3, where const is O(1). Nevertheless, the dominant region for the integration over z in Eq. 4.15 is for kzkg1, and thus (kz)1/2(kz)1/3. It is for this reason that Eq. 4.11 does not accurately reflect the behavior for values of kz1, but this has no effect on the final result in Eq. 4.15.
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  20. Note that we obtain j, depending on whether 1ε lies inside or outside the unit circle. It is for this reason that we used the losses at r=b to determine the appropriate sign in Eq. C16.

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