In an earlier paper, the contribution of the meson current to the electromagnetic structure of the nucleon was calculated by use of the dispersion relations for pion-nucleon scattering. Here the contribution of the nucleon current to the electromagnetic structure of the neutron is obtained analogously by use of the dispersion relations for neutron-proton scattering. Only the contribution from the one-pion and two-pion states of nucleon-nucleon scattering is considered. It is found that both states reduce the neutron-electron potential, i.e., leads to a smaller charge radius of the neutron. The contribution from the deuteron state is shown to be negligible. The resulting mean-square radii of the neutron, including the contributions of both meson and nucleon current, are ${(0.23\mathrm{}\times {10}^{-13\mathrm{}}\mathrm{c}\mathrm{m})}^2$ for the charge distribution and ${(0.41\mathrm{}\times {10}^{-13\mathrm{}}\mathrm{c}\mathrm{m})}^2$ for the magnetic moment distribution with $f^2=0.08\mathrm{}$.

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